zebra: Fix wrong debug macro in `release_srv6_sid_func_explicit`

`ZEBRA_DEBUG_SRV6` is not the correct macro to evaluate if SRv6 debug is enabled or not.

The correct macro is `IS_ZEBRA_DEBUG_SRV6`.

Fix this by replacing `ZEBRA_DEBUG_SRV6` with `IS_ZEBRA_DEBUG_SRV6`.

Signed-off-by: Carmine Scarpitta <cscarpit@cisco.com>

diff --git a/zebra/zebra_srv6.c b/zebra/zebra_srv6.c
index b87501b7553a8f927a986c06a0d62d594ccd6273..86ff81c4be7949b8515580fb90b7ae8f38729bde 100644 (file)
--- a/zebra/zebra_srv6.c
+++ b/zebra/zebra_srv6.c
@@ -1918,7 +1918,7 @@ static bool release_srv6_sid_func_explicit(struct zebra_srv6_sid_block *block,
                zebra_srv6_sid_func_free(sid_func_ptr);
        }
 
-       if (ZEBRA_DEBUG_SRV6)
+       if (IS_ZEBRA_DEBUG_SRV6)
                zlog_debug("%s: released explicit SRv6 SID function %u from block %pFX",
                           __func__, sid_func, &block->prefix);